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27x^2-81=0
a = 27; b = 0; c = -81;
Δ = b2-4ac
Δ = 02-4·27·(-81)
Δ = 8748
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8748}=\sqrt{2916*3}=\sqrt{2916}*\sqrt{3}=54\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-54\sqrt{3}}{2*27}=\frac{0-54\sqrt{3}}{54} =-\frac{54\sqrt{3}}{54} =-\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+54\sqrt{3}}{2*27}=\frac{0+54\sqrt{3}}{54} =\frac{54\sqrt{3}}{54} =\sqrt{3} $
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